Intermediate Algebra, Chapter 3, Test, Section Test, Problem 2

Determine the $x$- and $y$-intercept, and graph the equation $3x - 2y = 20$.

$x$-intercepts:


$
\begin{equation}
\begin{aligned}

3x - 2y =& 20
&& \text{Given equation}
\\
3x - 2(0) =& 20
&& \text{To find the $x$-intercepts, we let $y=0$ and solve for $x$}
\\
3x =& 20
&&
\\
x =& \frac{20}{3}

\end{aligned}
\end{equation}
$


The $x$-intercept is $\displaystyle \frac{20}{3}$.

$y$-intercepts:


$
\begin{equation}
\begin{aligned}

3x - 2y =& 20
&& \text{Given equation}
\\
3(0) - 2y =& 0
&& \text{To find the $y$-intercepts, we let $x=0$ and solve for $y$}
\\
-2y =& 20
&&
\\
y =& -10
&&

\end{aligned}
\end{equation}
$


The $y$-intercept is $-10$.