Find the equation of the line that has slope $\displaystyle -\frac{1}{2}$ and passes through the point $(6,-3)$ in...
a.) Slope intercept form.
b.) General form.
a.) Slope intercept form,
$
\begin{equation}
\begin{aligned}
y &= mx + b \\
\\
y &= -\frac{1}{2}x + b
\end{aligned}
\end{equation}
$
Solving for $b$ at point $(b,-3)$,
$
\begin{equation}
\begin{aligned}
-3 &= -\frac{1}{2} (6) + b\\
\\
-3 &= -3 + b\\
\\
b &= 0
\end{aligned}
\end{equation}
$
Thus the equation of the line is...
$\displaystyle y = -\frac{1}{2}x$
b.) General form,
$
\begin{equation}
\begin{aligned}
Ax + By + C &= 0 \\
\\
y &= - \frac{1}{2}x && \text{Multiply by } 2\\
\\
2y &= -x && \text{Add } x\\
\\
x + 2y &= 0
\end{aligned}
\end{equation}
$
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