x^2=12y Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola.

Let x^2=4py be equation of parabola. Then equation of directrix is y=-p coordinates of focus are (0,p) and axis of symmetry is y-axis.
In this case the equation of parabola is
x^2=12y
Therefore,
4p=12
p=3
Using the facts stated above we can write equation of directrix and coordinates of focus.
Directrix is line with equation y=-3 focus is the point with coordinates (0,3) and axis of symmetry is y-axis.                     
https://en.wikipedia.org/wiki/Parabola