g(t)=ln(t)/t^2Find the derivative of the function using the quotient rule.g'(t)={t^2[1/t]-ln(t)[2t]}/t^4 g'(t)=[t-2tln(t)]/t^4 g'(t)=(t(1-2ln(t)))/t^4 g'(t)=(1-2ln(t))/t^3 The derivative of g(t) is (1-2ln(t))/t^3.
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