h(t) = ln(t)/t Find the derivative of the function.

We'll use the formula of the derivative of a quotient:  (u/v)' = (u'v-u v')/v^2.  Here u=ln(t) and v=t, therefore u'=1/t and v'=1. So
h'(t) = (1/t *t - ln(t))/t^2 = (1 - ln(t))/t^2.