Sunday, July 2, 2017

Intermediate Algebra, Chapter 3, 3.6, Section 3.6, Problem 36

Determine the value of $x$ for each value of $f(x)$.

a.) $f(x) = 4$

Since $f(x) = y$, we want the value of $x$ that corresponds to $y = 4$. Locate $4$ on the $y$-axis. Moving across to the graph of $f$ and down to the $x$-axis gives $x = 3$. Thus, $f(3) = 4$.


b.) $f(x) = -2$

Since $f(x) = y$, we want the value of $x$ that corresponds to $y = -2$. Locate $-2$ on the $y$-axis. Moving across to the graph of $f$ and down to the $x$-axis gives $x = 0$. Thus, $f(0) = -2$.

c.) $f(x) = 0$

Since $f(x) = y$, we want the value of $x$ that corresponds to $y = 0$. Locate on the $y$-axis. Moving across to the graph of $f$ and down to the $x$-axis gives $x = 1$. Thus, $f(1) = 0$.

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