Tuesday, June 19, 2018

Beginning Algebra With Applications, Chapter 5, 5.3, Section 5.3, Problem 50

Graph $\displaystyle y = \frac{1}{2}x$ by using the slope and $y$-intercept.

$y$-intercept:


$
\begin{equation}
\begin{aligned}

y =& \frac{1}{2}x
&& \text{Given equation}
\\
y =& \frac{1}{2} (0)
&& \text{To find the $y$-intercept, let } x = 0
\\
y =& 0
&&

\end{aligned}
\end{equation}
$


The $y$-intercept is $(0,0)$


$
\begin{equation}
\begin{aligned}

m =& \frac{\text{change in } y}{\text{change in } x}
\\
\\
m =& \frac{1}{2}

\end{aligned}
\end{equation}
$


Beginning at the $y$-intercept, move to the right 2 units and then up 1 unit.







$(2, 1)$ are the coordinates of a second point on the graph.

Draw a line through $(0,0)$ and $(2, 1)$

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