Tuesday, July 3, 2018

Intermediate Algebra, Chapter 3, 3.3, Section 3.3, Problem 64

Determine an equation of the line passing through the points $\displaystyle \left( - \frac{4}{9}, -6 \right)$ and $\displaystyle \left( \frac{12}{7}, -6 \right)$.

(a) Write the equation in standard form.

Using the Slope Formula,

$\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-6-(-6)}{\displaystyle \frac{12}{7} - \left( - \frac{4}{9} \right)} = \frac{0}{\displaystyle \frac{136}{63}} = 0$

Since the slope is , this is a horizontal line through the point $(a,b)$ has equation $y=b$. Here the $y$-coordinate is $-6$, so the equation is $y=-6$.

(b) Write the equation in slope-intercept form.

The equation $y = -6$ is also the slope intercept form.

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