7^(3x+4)=49^(2x+1)
To solve, factor the 49.
7^(3x+4)=(7^2)^(2x+1)
To simplify the right side, apply the exponent property (a^m)^n=a^(m*n) .
7^(3x+4)=7^(4x+2)
Since the two sides have the same base, to solve for the value of x, set the exponent at the left equal to the exponent at the right side.
3x + 4= 4x + 2
3x - 4x = 2 - 4
-x=-2
x=2
Therefore, the solution is x = 2 .
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