Determine which statement is true for all real numbers.
a.) $||x| - |y|| \leq |x| - |y|$
b.) $||x| - |y|| = |x| - |y|$
c.) $||x| - |y|| \geq |x| - |y|$
If we let $x = -2$ and $y = 3$, then we substitute this to the given statement. We have
a.)
$
\begin{equation}
\begin{aligned}
||-2| - |3|| & \leq |-2|-|3|
\\
|2-3| & \leq 2-3
\\
|-1| & \leq -1
\\
1 & \leq -1
\end{aligned}
\end{equation}
$
The statement is false.
b.)
$
\begin{equation}
\begin{aligned}
||-2| - |3|| =& |-2| - |3|
\\
|2-3| =& 2-3
\\
|-1| =& -1
\\
1 =& -1
\end{aligned}
\end{equation}
$
The statement is false.
c.)
$
\begin{equation}
\begin{aligned}
||-2| - |3|| \geq & |-2| - |3|
\\
|2 -3| =& 2-3
\\
|-1| =& -1
\\
1 \geq & -1
\end{aligned}
\end{equation}
$
The statement is true.
So the statement that is true for all real numbers is $||x| - |y|| \geq |x| - |y|$
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