Single Variable Calculus, Chapter 5, 5.4, Section 5.4, Problem 8

Determine the general indefinite integral $\displaystyle \int \left( y^3 + 1.8y^2 - 2.4y \right) dy$

$
\begin{equation}
\begin{aligned}
\int \left( y^3 + 1.8y^2 - 2.4y \right) dy &= \int y^3 dy + \int 1.8 y^2 dy - \int 2.4 y dy\\
\\
\int \left( y^3 + 1.8y^2 - 2.4y \right) dy &= \int y^3 dy + 1.8 \int y^2 dy - 2.4 \int y dy\\
\\
\int \left( y^3 + 1.8y^2 - 2.4y \right) dy &= \frac{y{3+1}}{3+1} + 1.8 \left( \frac{y^{2+1}}{2+1} \right) - 2.4 \left( \frac{y^{1+1}}{1+1} \right) + C\\
\\
\int \left( y^3 + 1.8y^2 - 2.4y \right) dy &= \frac{y^4}{4} + 1.8 \left( \frac{y^3}{3} \right) - 2.4 \left( \frac{y^2}{2} \right) + C\\
\\
\int \left( y^3 + 1.8y^2 - 2.4y \right) dy &= \frac{y^4}{4} + 0.6 y^3 - 1.2 y^2 + C
\end{aligned}
\end{equation}
$