Suppose that a card is drawn randomly from a standard 52-card deck. Find the probability of the given event.
a.) The card drawn is a heart.
There are four different suits on the cards namely hearts, spades, diamonds and clubs. Each of which has 13 cards. So the probability of drawing a heart is
$\displaystyle \frac{13}{52} = \frac{1}{4}$
b.) The card drawn is either a heart or a spade.
The probability of drawing a heart or a spade is
$\displaystyle \frac{13}{52} + \frac{13}{52} = \frac{1}{4} + \frac{1}{4} = \frac{2}{4} = \frac{1}{2}$
c.) The card drawn is a heart, a diamond, or a spade.
In this case, we can use the probability of the complement of an event. If we get the probability of getting a club, we have
$\displaystyle \frac{13}{52} = \frac{1}{4}$
Thus, the probability of getting a heart, a diamond or a spade is
$\displaystyle 1 - \frac{1}{4} = \frac{3}{4}$
Thursday, February 7, 2013
College Algebra, Chapter 10, 10.3, Section 10.3, Problem 12
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