Hello!
To determine where a function is concave upward or downward, we may use the second derivative. This function is defined everywhere, differentiable and second differentiable everywhere, so Concavity Theorem is applicable.
f'(x) = -24*(2x)/(x^2+12)^2 = -48*(x)/(x^2+12)^2,
f''(x) = -48*((x^2+12)^2 - x*[(x^2+12)^2]')/(x^2+12)^4 =
-48*((x^2+12)^2 - x*2*(x^2+12)*2x)/(x^2+12)^4 =
-48*(x^2+12 - 4x^2)/(x^2+12)^3 =-48*3*(4 - x^2)/(x^2+12)^3 =
= 48*3*(x^2-4)/(x^2+12)^3.
We see that f''(x)=0 for x=-2 and x=2. Moreover, it is negative inside (-2, 2) and is positive outside (the denominator is always positive).
The answer: f is concave upward at (-oo, -2) uuu(2, +oo) and is concave downward at (-2, 2).
Sunday, May 19, 2013
Calculus of a Single Variable, Chapter 3, 3.4, Section 3.4, Problem 7
Subscribe to:
Post Comments (Atom)
Summarize the major research findings of "Toward an experimental ecology of human development."
Based on findings of prior research, the author, Bronfenbrenner proposes that methods for natural observation research have been applied in ...
-
Show that $\displaystyle a(t) = v(t) \frac{dV}{ds}$ of a particle that moves along a straight line with displacement $s(t)$, velocity $v(t)$...
-
Find the indefinite integral $\displaystyle \int \sec^4 \left( \frac{x}{2} \right) dx$. Illustrate by graphing both the integrand and its an...
-
Determine the area of the region bounded by the hyperbola $9x^2 - 4y^2 = 36$ and the line $ x= 3$ By using vertical strips, Si...
-
Determine $\displaystyle \frac{dy}{dx}$ of $y^5 + x^2y^3 = 1 + x^4 y$ by Implicit Differentiation. $\displaystyle \frac{d}{dx}(y^5) + ...
-
Find the integral $\displaystyle \int^1_0 \frac{1}{\sqrt{16 t^2 + 1}} dt$ If we let $u = 4t$, then $du = 4dt$, so $\displaystyle dt = \frac{...
-
The narrator of "Sonny's Blues" describes the neighborhood as "filled with a hidden menace which was its very breath of l...
-
Given y=cos(2x), y=0 x=0,x=pi/4 so the solid of revolution about x-axis is given as V = pi * int _a ^b [R(x)^2 -r(x)^2] dx here R(x) =cos(2x...
No comments:
Post a Comment