In general, Jess's family does not have a big problem with Jess being friends with Leslie. That does not mean they are all completely supportive of Jess, though. Jess's dad is probably the least supportive of the friendship. He has some fairly archaic ideas about how boys and girls should associate. He also doesn't like how Leslie tends to pull his only son away from doing "manly" things. Brenda and Ellie don't seem to have a problem with Jess and Leslie being friends, either. They tease Jess a lot about it, but I don't believe that means they are against the friendship. I would say that they like that Jess and Leslie hang out together because it gives Brenda and Ellie the opportunity to tease Jess more. May Belle is the most positive about the friendship between Jess and Leslie. That's why she is always trying to tag along and find out what they do together in the woods.
Subscribe to:
Post Comments (Atom)
Summarize the major research findings of "Toward an experimental ecology of human development."
Based on findings of prior research, the author, Bronfenbrenner proposes that methods for natural observation research have been applied in ...
-
Find the indefinite integral $\displaystyle \int \sec^4 \left( \frac{x}{2} \right) dx$. Illustrate by graphing both the integrand and its an...
-
x=4cost y=2sint First, take the derivative of x and y with respect to t. dx/dt=-4sint dy/dt=2cost Then, determine the first derivative dy/dx...
-
Ethno-nationalism is defined as "advocacy of or support for the political interests of a particular ethnic group, especially its nation...
-
Determine the area of the region bounded by the hyperbola $9x^2 - 4y^2 = 36$ and the line $ x= 3$ By using vertical strips, Si...
-
Both boys are very charismatic and use their charisma to persuade others to follow them. The key difference of course is that Ralph uses his...
-
Equation of a tangent line to the graph of function f at point (x_0,y_0) is given by y=y_0+f'(x_0)(x-x_0). The first step to finding eq...
-
Determine $\displaystyle \frac{dy}{dx}$ of $y^5 + x^2y^3 = 1 + x^4 y$ by Implicit Differentiation. $\displaystyle \frac{d}{dx}(y^5) + ...
No comments:
Post a Comment