We are asked to use the derivative of y=5000/(1+e^(2x)) to determine if the function has an inverse. There is a theorem that states that if a function is monotonic (meaning the function is always non-increasing or non-decreasing) then it has an inverse. So, to show a function is monotonic, we need to check if its derivative is either positive or negative for all values in the domain.
By the quotient rule, the derivative is:
y'=(-5000(2e^(2x)))/(1+e^(2x))^2
The denominator is positive for all x. The 2e^(2x) term is positive for all x so the numerator is negative for all x. Therefore the derivative is always negative and the function decreases on its entire domain.
Thus the function has an inverse.
The graph of the function (black):
http://www.sosmath.com/calculus/diff/der12/der12.html
Sunday, April 1, 2018
5000/(1 + e^(2x)) = 2 Use the derivative to determine whether the function is strictly monotonic on its entire domain and therefore has an inverse function.
Subscribe to:
Post Comments (Atom)
Summarize the major research findings of "Toward an experimental ecology of human development."
Based on findings of prior research, the author, Bronfenbrenner proposes that methods for natural observation research have been applied in ...
-
Find the indefinite integral $\displaystyle \int \sec^4 \left( \frac{x}{2} \right) dx$. Illustrate by graphing both the integrand and its an...
-
x=4cost y=2sint First, take the derivative of x and y with respect to t. dx/dt=-4sint dy/dt=2cost Then, determine the first derivative dy/dx...
-
Ethno-nationalism is defined as "advocacy of or support for the political interests of a particular ethnic group, especially its nation...
-
Determine the area of the region bounded by the hyperbola $9x^2 - 4y^2 = 36$ and the line $ x= 3$ By using vertical strips, Si...
-
Both boys are very charismatic and use their charisma to persuade others to follow them. The key difference of course is that Ralph uses his...
-
Equation of a tangent line to the graph of function f at point (x_0,y_0) is given by y=y_0+f'(x_0)(x-x_0). The first step to finding eq...
-
Determine $\displaystyle \frac{dy}{dx}$ of $y^5 + x^2y^3 = 1 + x^4 y$ by Implicit Differentiation. $\displaystyle \frac{d}{dx}(y^5) + ...
No comments:
Post a Comment