You need to evaluate the volume using the washer method, such that:
V = pi*int_a^b(f^2(x) - g^2(x))dx
You need first to determine the endpoints, hence you need to solve for y the following equation, such that:
y^2 = 1 - y^2
2y^2 = 1 => y^2 = 1/2 => y_(1,2) = +-(sqrt2)/2
V = pi*int_(-(sqrt2)/2)^((sqrt2)/2) ((3 - y^2)^2 - (3 - 1 + y^2)^2)dy
V = pi*int_(-(sqrt2)/2)^((sqrt2)/2) (9 - 6y^2 + y^4 - 4 - 4y^2 - y^4)dy
V = pi*int_(-(sqrt2)/2)^((sqrt2)/2) (5 - 10y^2)dy
V = pi*(int_(-(sqrt2)/2)^((sqrt2)/2) 5dy - int_(-(sqrt2)/2)^((sqrt2)/2) 10y^2dy)
V = pi*(5y|_(-(sqrt2)/2)^((sqrt2)/2) - 10y^3/3|_(-(sqrt2)/2)^((sqrt2)/2))
V = pi*(5((sqrt2)/2+(sqrt2)/2) - 10/3(2sqrt2/8 + 2sqrt2/8))
V = pi*(5sqrt2 - 10*sqrt2/6)
V = (20*pi*sqrt2)/6
V = (10*pi*sqrt2)/3
Hence, evaluating the volume of the solid obtained by rotating the region bounded by the given curves, about x = 3, yields V = (10*pi*sqrt2)/3.
Sunday, May 26, 2019
Calculus: Early Transcendentals, Chapter 6, 6.2, Section 6.2, Problem 17
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