a.) The graph of the distance as a function of time of a particle is shown below suppose that it starts moving to the
right along a horizontal line. When is the particle moving to the right? Moving to the left? Standing still?
$
\begin{array}{|c|c|c|}
\hline\\
\text{Right} & \text{Left} & \text{Standing Still}\\
\hline\\
0 < t < 1 & 2 < t < 3 & 1 < t < 2\\
\text{and} & & \text{and}\\
4 < t < 6 & & 3 < t < 4\\
& & \\
\hline
\end{array}
$
b.) Draw the graph of the velocity function.
The graph is obtained by evaluating the slopes of the curve in the intervals given in part(a) using point slope form.
For example @ $0 < t < 1$
$\displaystyle \text{Velocity } = m = \frac{3-0}{1-0} = 3$
Wednesday, March 30, 2016
Single Variable Calculus, Chapter 3, 3.1, Section 3.1, Problem 11
Subscribe to:
Post Comments (Atom)
Summarize the major research findings of "Toward an experimental ecology of human development."
Based on findings of prior research, the author, Bronfenbrenner proposes that methods for natural observation research have been applied in ...
-
Find the indefinite integral $\displaystyle \int \sec^4 \left( \frac{x}{2} \right) dx$. Illustrate by graphing both the integrand and its an...
-
Determine $\displaystyle \frac{dy}{dx}$ of $y^5 + x^2y^3 = 1 + x^4 y$ by Implicit Differentiation. $\displaystyle \frac{d}{dx}(y^5) + ...
-
Determine the area of the region bounded by the hyperbola $9x^2 - 4y^2 = 36$ and the line $ x= 3$ By using vertical strips, Si...
-
Find the integral $\displaystyle \int^1_0 \frac{1}{\sqrt{16 t^2 + 1}} dt$ If we let $u = 4t$, then $du = 4dt$, so $\displaystyle dt = \frac{...
-
Determine the integral $\displaystyle \int \frac{\sin^3 (\sqrt{x})}{\sqrt{x}} dx$ Let $u = \sqrt{x}$, then $\displaystyle du = \frac{1}{2 \s...
-
Given y=cos(2x), y=0 x=0,x=pi/4 so the solid of revolution about x-axis is given as V = pi * int _a ^b [R(x)^2 -r(x)^2] dx here R(x) =cos(2x...
-
Anthony certainly cheats on Gloria. During the war, when he was stationed in South Carolina, he had an affair with a local girl by the name ...
No comments:
Post a Comment