Find the probability that the indicated card is drawn at random form a 52-card deck.
a.) An ace
There are four aces in a deck of a card. Thus, the probability in this case is
$\displaystyle \frac{4}{52} = \frac{1}{13}$
b.) An ace or a jack
Since an ace can never be jack, then the probability of this mutually exclusive event is
$\displaystyle \frac{4}{52} + \frac{4}{52} = \frac{8}{52} = \frac{2}{13}$
c.) An ace or a spade
Since there is an ace of spades we have an intersection of two events. Thus, the probability of union of this two events is
$\displaystyle \frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{4}{13}$
d.) A red ace
We know that there are only two red aces. Precisely ace of diamonds and ace of hearts. Thus, the probability in this case is
$\displaystyle \frac{2}{52} = \frac{1}{26}$
Tuesday, June 26, 2012
College Algebra, Chapter 10, Review Exercises, Section Review Exercises, Problem 28
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