Sunday, December 3, 2017

College Algebra, Chapter 8, Review Exercises, Section Review Exercises, Problem 10

Determine the center, vertices, foci, eccentricity and lengths of the major and minor axes of the ellipse $\displaystyle \frac{x^2}{49} + \frac{y^2}{9} = 1$. Then sketch its graph.

The equation has the form $\displaystyle \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ with horizontal major since the denominator of $x^2$ is larger. This gives $a^2 = 4a$ and $b^2 = 9$, so $c^2 = a^2 - b^2 = 49- 9 = 40$. Thus, $a = 7, b = 3$ and $c = \sqrt{40} = 2 \sqrt{10}$. Then, the following is determined as

vertices $(\pm a, 0) \to (\pm 7,0)$

foci $(\pm c, 0) \to (\pm 2 \sqrt{10}, 0)$

eccentricity $\displaystyle \frac{c}{a} \to \frac{2 \sqrt{10}}{7}$

length of the major axis $2a \to 14$

length of the minor axis $2b \to 6$

Therefore, the graph is

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