a.) What is the first derivative test?
b.) What is the second derivative test? Under what circumstances is it inconclusive? What must be done if it fails?
a.) The first derivative test is used to determine if the critical number is either a local maximum or a local minimum. Here's how it works.
The first derivative test. Suppose that $c$ is a critical number of a continuous function $f$.
If $f'$ changes from positive to negative at $c$, then $f$ has a local maximum.
If $f'$ changes from negative to positive at $c$, then $f$ has a local minimum.
If $f'$ does not change sign at $c$, then $f$ has no local maximum or local minimum at $c$.
b.) The second derivative test is used to determine the concavity of the function on the given interval. If $f''(x) > 0$ for a specific interval, then the graph of $f$ is concave upward. On the other hand, if $f''(x) < 0$ for a specific interval, then the graph of $f$ is concave downward. The second derivative test is inconclusive when $f''(x) = 0$. In that case we will use the first derivative test.
Wednesday, June 6, 2018
Single Variable Calculus, Chapter 4, 4.3, Section 4.3, Problem 4
Subscribe to:
Post Comments (Atom)
Summarize the major research findings of "Toward an experimental ecology of human development."
Based on findings of prior research, the author, Bronfenbrenner proposes that methods for natural observation research have been applied in ...
-
Find the indefinite integral $\displaystyle \int \sec^4 \left( \frac{x}{2} \right) dx$. Illustrate by graphing both the integrand and its an...
-
Determine $\displaystyle \frac{dy}{dx}$ of $y^5 + x^2y^3 = 1 + x^4 y$ by Implicit Differentiation. $\displaystyle \frac{d}{dx}(y^5) + ...
-
Determine the area of the region bounded by the hyperbola $9x^2 - 4y^2 = 36$ and the line $ x= 3$ By using vertical strips, Si...
-
Find the integral $\displaystyle \int^1_0 \frac{1}{\sqrt{16 t^2 + 1}} dt$ If we let $u = 4t$, then $du = 4dt$, so $\displaystyle dt = \frac{...
-
Determine the integral $\displaystyle \int \frac{\sin^3 (\sqrt{x})}{\sqrt{x}} dx$ Let $u = \sqrt{x}$, then $\displaystyle du = \frac{1}{2 \s...
-
Gertrude's comment "The lady protests too much, methinks" in act 3, scene 2, of Shakespeare's Hamlet exposes her own guilt...
-
Given y=cos(2x), y=0 x=0,x=pi/4 so the solid of revolution about x-axis is given as V = pi * int _a ^b [R(x)^2 -r(x)^2] dx here R(x) =cos(2x...
No comments:
Post a Comment