Monday, December 3, 2012

College Algebra, Chapter 4, 4.4, Section 4.4, Problem 24

Determine all rational zeros of the polynomial $P(x) = x^3 - 4x^2 - 11x + 30$, and write the polynomial in factored form.

The leading coefficient of $P$ is $1$, so all the rational zeros are integers:

They are divisors of the constant term $30$. Thus, the possible candidates are

$\pm 1, \pm 2, \pm 3, \pm 5, \pm 6, \pm 10, \pm 15, \pm 30$

Using Synthetic Division







We find that $1$ is not a zero but that $2$ is a zero and that $P$ factors as

$x^3 - 4x^2 - 11x + 30 = (x - 2)(x^2 - 2x - 15)$

We now factor $x^2 - 2x - 15$ using trial and error, so


$
\begin{equation}
\begin{aligned}

x^3 - 4x^2 - 11x + 30 =& (x - 2)(x - 5)(x + 3)

\end{aligned}
\end{equation}
$


Therefore, the zeros of $P$ are $2, 5$ and $-3$.

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