Calculus: Early Transcendentals, Chapter 2, 2.2, Section 2.2, Problem 1

The equation lim_(x->2) f(x) = 5 means that for the values of x approaching to 2, the values of the function f (x) are being 5. As we go the closer to the x values of 2, the closer the resulting f (x) values are supposed to get to 5.
Yes,It is possible for the limit to equal 5 even though f (2) = 3. The function f (x) = [[(1 - x^2)]] , the limit as x approaches 0 is 0, but f (0) = 1. so now we can create a relation as the function
f (x) = 5- 2 [[(1- (x-2)^2)]]
and for this function, the limit as x approaches 2 is 5, but f (2) = 3