Determine an equation for the line with a slope $\displaystyle \frac{1}{2}$ containing the point $(3,1)$. Express your answer using the general form or the slope intercept form of the equation of a line, which ever you prefer.
Using the Point Slope Form to find the equation
$
\begin{equation}
\begin{aligned}
y - y_1 =& m(x- x_1)
&& \text{Point Slope Form}
\\
\\
y - 1 =& \frac{1}{2} (x-3)
&& \text{Substitute } m = \frac{1}{2}, x = 3 \text{ and } y = 1
\\
\\
y =& \frac{1}{2}x - \frac{3}{2} + 1
&& \text{Simplify}
\\
y =& \frac{1}{2}x - \frac{1}{2}
&& \text{Slope Intercept Form}
\\
\text{or} &
&&
\\
\frac{1}{2}x - y =& \frac{1}{2}
&& \text{General Form}
\end{aligned}
\end{equation}
$
Saturday, November 17, 2012
Precalculus, Chapter 1, 1.3, Section 1.3, Problem 48
Subscribe to:
Post Comments (Atom)
Summarize the major research findings of "Toward an experimental ecology of human development."
Based on findings of prior research, the author, Bronfenbrenner proposes that methods for natural observation research have been applied in ...
-
Find the indefinite integral $\displaystyle \int \sec^4 \left( \frac{x}{2} \right) dx$. Illustrate by graphing both the integrand and its an...
-
Determine $\displaystyle \frac{dy}{dx}$ of $y^5 + x^2y^3 = 1 + x^4 y$ by Implicit Differentiation. $\displaystyle \frac{d}{dx}(y^5) + ...
-
Determine the area of the region bounded by the hyperbola $9x^2 - 4y^2 = 36$ and the line $ x= 3$ By using vertical strips, Si...
-
Find the integral $\displaystyle \int^1_0 \frac{1}{\sqrt{16 t^2 + 1}} dt$ If we let $u = 4t$, then $du = 4dt$, so $\displaystyle dt = \frac{...
-
Determine the integral $\displaystyle \int \frac{\sin^3 (\sqrt{x})}{\sqrt{x}} dx$ Let $u = \sqrt{x}$, then $\displaystyle du = \frac{1}{2 \s...
-
Gertrude's comment "The lady protests too much, methinks" in act 3, scene 2, of Shakespeare's Hamlet exposes her own guilt...
-
Given y=cos(2x), y=0 x=0,x=pi/4 so the solid of revolution about x-axis is given as V = pi * int _a ^b [R(x)^2 -r(x)^2] dx here R(x) =cos(2x...
No comments:
Post a Comment