You need to use the dot product to find the cosine of the angle between the vectors v and w, such that:
cos alpha = (v*w)/(|v|*|w|)
You need to evaluate the product of the vectors v and w, v = v_x*i + v_y*j, w = w_x*i + w_y*j , such that:
v*w = v_x*w_x + v_y*w_y
v*w = 1*2 + 1*(-2)
v*w = 2- 2
v*w = 0
Since the product of vectors v*w is 0, it is no need to evaluate (|v|*|w|) since cos alpha = 0.
cos alpha = 0 => alpha = pi/2
Hence, evaluating the angle between the vectors v and w, yields alpha = pi/2.
Wednesday, August 2, 2017
Precalculus, Chapter 6, 6.3, Section 6.3, Problem 79
Subscribe to:
Post Comments (Atom)
Summarize the major research findings of "Toward an experimental ecology of human development."
Based on findings of prior research, the author, Bronfenbrenner proposes that methods for natural observation research have been applied in ...
-
Find the indefinite integral $\displaystyle \int \sec^4 \left( \frac{x}{2} \right) dx$. Illustrate by graphing both the integrand and its an...
-
Determine $\displaystyle \frac{dy}{dx}$ of $y^5 + x^2y^3 = 1 + x^4 y$ by Implicit Differentiation. $\displaystyle \frac{d}{dx}(y^5) + ...
-
Determine the area of the region bounded by the hyperbola $9x^2 - 4y^2 = 36$ and the line $ x= 3$ By using vertical strips, Si...
-
Find the integral $\displaystyle \int^1_0 \frac{1}{\sqrt{16 t^2 + 1}} dt$ If we let $u = 4t$, then $du = 4dt$, so $\displaystyle dt = \frac{...
-
Determine the integral $\displaystyle \int \frac{\sin^3 (\sqrt{x})}{\sqrt{x}} dx$ Let $u = \sqrt{x}$, then $\displaystyle du = \frac{1}{2 \s...
-
Gertrude's comment "The lady protests too much, methinks" in act 3, scene 2, of Shakespeare's Hamlet exposes her own guilt...
-
Given y=cos(2x), y=0 x=0,x=pi/4 so the solid of revolution about x-axis is given as V = pi * int _a ^b [R(x)^2 -r(x)^2] dx here R(x) =cos(2x...
No comments:
Post a Comment