Intermediate Algebra, Chapter 3, Test, Section Test, Problem 10

Determine an equation of the line "through $(4,-1); m = -5$", and write it in the following form:

a.) Slope-intercept form

Using Point Slope Form


$
\begin{equation}
\begin{aligned}

y - y_1 =& m(x - x_1)
&& \text{Point Slope Form}
\\
\\
y -(-1) =& -5(x-4)
&& \text{Substitute } x = 4, y = -1 \text{ and } m = -5
\\
\\
y + 1 =& -5x + 20
&& \text{Distributive Property}
\\
\\
y =& -5x + 19
&& \text{Slope Intercept Form}

\end{aligned}
\end{equation}
$



b.) Standard Form


$
\begin{equation}
\begin{aligned}

& y = -5x + 19
&& \text{Slope Intercept Form}
\\
& 5x + y = 19
&& \text{Standard Form}


\end{aligned}
\end{equation}
$