The best answer to this question is "it depends." It depends on the magnification power of the light microscope and the size of the mitochondria that you are trying to look at. Mitochondria can vary greatly in size. As a result, only the largest mitochondria can be seen with the highest magnification of light microscopes. A light microscope can magnify an image up to 400 times, and the limit of its resolution is about .2 microns. This is enough magnification power and resolution to examine larger mitochondria and things like lysosomes, nucleuses, and large vacuoles, but to examine the smaller examples, you will need something like an electron microscope. The magnification of those microscopes is up to 500,000 times and provides resolution down to 1 nanometer.
http://medcell.med.yale.edu/histology/cell_lab.php
https://www.sciencelearn.org.nz/images/534-mitochondria-under-the-microscope
Friday, November 24, 2017
Can mitochondria be seen with the light microscope?
Subscribe to:
Post Comments (Atom)
Summarize the major research findings of "Toward an experimental ecology of human development."
Based on findings of prior research, the author, Bronfenbrenner proposes that methods for natural observation research have been applied in ...
-
Find the indefinite integral $\displaystyle \int \sec^4 \left( \frac{x}{2} \right) dx$. Illustrate by graphing both the integrand and its an...
-
Determine $\displaystyle \frac{dy}{dx}$ of $y^5 + x^2y^3 = 1 + x^4 y$ by Implicit Differentiation. $\displaystyle \frac{d}{dx}(y^5) + ...
-
Determine the area of the region bounded by the hyperbola $9x^2 - 4y^2 = 36$ and the line $ x= 3$ By using vertical strips, Si...
-
Find the integral $\displaystyle \int^1_0 \frac{1}{\sqrt{16 t^2 + 1}} dt$ If we let $u = 4t$, then $du = 4dt$, so $\displaystyle dt = \frac{...
-
Determine the integral $\displaystyle \int \frac{\sin^3 (\sqrt{x})}{\sqrt{x}} dx$ Let $u = \sqrt{x}$, then $\displaystyle du = \frac{1}{2 \s...
-
Gertrude's comment "The lady protests too much, methinks" in act 3, scene 2, of Shakespeare's Hamlet exposes her own guilt...
-
Given y=cos(2x), y=0 x=0,x=pi/4 so the solid of revolution about x-axis is given as V = pi * int _a ^b [R(x)^2 -r(x)^2] dx here R(x) =cos(2x...
No comments:
Post a Comment