Wednesday, May 23, 2018

Glencoe Algebra 2, Chapter 2, 2.6, Section 2.6, Problem 56

Hi!The slope (m) as given in the question is 3 which means m=3.
You are given points (-2,4) through which the line passes.
As you may recall, the slope intercept form is y=m*x+b, where:
m=slope = 3
x=x point = -2
y=y point = 4
b=constant = ?(you have to figure it out!)
So you just plug in the values for the variables and solve for b

4 = 3*(-2)+b
4 = -6+b
b= 10
Once you have solved for b, you simply plug it in the equation y=m*x+b
So, y = 3x + 10 is the equation that has a slope of 3 and passes through (-2,4)
Note: For the final equation, you only need to plug in the value of m and b. ( as seen above) For y and x you just write y and x , not the numerical value.
Hope this helps!

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