College Algebra, Chapter 5, 5.2, Section 5.2, Problem 60

Graph the function $y = 1 + \ln(-x)$, not by plotting points, but by starting from the graphs of family of Logarithmic functions. State the domain, range and asymptote.







We start with the graph of $y = \ln (x)$ and reflect it to the $y$-axis then shift $1$ unit upward to have the graph of $y = 1 + \ln (-x)$. Its domain is $(- \infty, 0)$ and its range is all reals. Also the vertical asymptote is $x = 0$.